Discover the Largest Ion in an Isoelectronic Series: S2-, Cl-, K+, and Ca2+

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The discussion centers on determining the largest ion within the isoelectronic series consisting of S2−, Cl−, K+, and Ca2+. An isoelectronic series refers to ions that have the same number of electrons but differ in nuclear charge. The atomic radius trends indicate that atomic size increases as one moves left and down the periodic table. In this case, the size of the ions is influenced by the effective nuclear charge, which is the net positive charge experienced by electrons. Cations, which have a higher proton count relative to their electron count, are typically smaller than anions. Therefore, among the ions listed, S2− is the largest due to having the least number of protons compared to the number of electrons, leading to a weaker effective nuclear charge and a larger ionic radius.
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15. The following ions comprise an isoelectronic series: S2, Cl, K+, and Ca2+
Which is the largest ion?

A. S2-
B. Cl-
C. K+
D. Ca2+
E. All should be the same size.

Don't even know what one is.
 
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What are your periodic trends for atomic size?
 
Atomic radius increases to the left and down.
 
Does the term "isoelectronic series" do anything for this problem?
 
It just means that all ions have exactly the same number of electrons, the only thing that changes is nucleus charge.
 
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It quite self-explanatory, atoms with the same number of electrons. You should be able to figure out the electron number in a neutral atom of the element, and further deduce the electron number of a corresponding ion.

In reference to the size of each of these, you'll need to consider the relative proton number with the electron number, effective nuclear charge. Typically, a isoelectronic cation is smaller than the anion because you've got the same number of electrons for both with a smaller proton number for the latter.
 
Not to blow any trumpets here but this essentially summarizes what has been said above by Borek and GenChemTutor, about comparing radii among isoelectronic ions.
 
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