Disp. with Constant Accel. Formula Help

  • Thread starter Thread starter shyboyswin
  • Start date Start date
  • Tags Tags
    Constant Formula
AI Thread Summary
A jet plane landing at +100 m/s with a maximum deceleration of -5.0 m/s² needs to determine if it can stop within an 800-meter runway. The initial velocity and acceleration values are correctly identified, but there is confusion regarding the application of the equations. The first equation used for time calculation contains a sign error, leading to incorrect results. Once the correct time is determined, the second equation can be applied to find the stopping distance needed. Properly applying these formulas will clarify whether the plane can safely land on the runway.
shyboyswin
Messages
9
Reaction score
0

Homework Statement


A jet plane lands with a velocity of +100 m/s and can accelerate at a maximum rate of -5.0 m/s2 as it comes to rest. Can this plane land at an airport where the runway is 800 meters long?

v_i = +100 m/s
a = -5.0 m/s^2

Homework Equations


The only equations in the chapter are as follows, but I don't think either can help me:
a_{avg} = \frac{\Delta x}{\Delta t}
\Delta x = \frac{1}{2}(v_i +v_f)\Delta t

The Attempt at a Solution


I have attempted the following, but the answer does not seem to make any sense to me, since I need a distance and not a time.

\frac{+100 m/s}{-5.0 m/s^2} = -20 s
 
Physics news on Phys.org
shyboyswin said:

Homework Statement


A jet plane lands with a velocity of +100 m/s and can accelerate at a maximum rate of -5.0 m/s2 as it comes to rest. Can this plane land at an airport where the runway is 800 meters long?

v_i = +100 m/s
a = -5.0 m/s^2

Homework Equations


The only equations in the chapter are as follows, but I don't think either can help me:
a_{avg} = \frac{\Delta x}{\Delta t}
\Delta x = \frac{1}{2}(v_i +v_f)\Delta t

The Attempt at a Solution


I have attempted the following, but the answer does not seem to make any sense to me, since I need a distance and not a time.

\frac{+100 m/s}{-5.0 m/s^2} = -20 s
Shyboyswin, welcome to PF! Your first equation is not correct, looks like you may have made a typo error, because you have used the correct magnitude values in your calculation for time, although you're messing up your plus and minus signs. Once you get the time, use your 2nd equation to calculate the required stopping distance.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top