Displacement current in Maxwell equations

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snyski
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Does anyone know how to solve or at least how to begin solving the following problem?:

Prove that displacement current in the Maxwell equations can be neglected if characteristic time τ of changing electromagnetic field in the system satisfies to the following condition: τ >> L/c where L is the characteristic size of this system and c is light speed. (Hint: time derivative of some variable y can be approximated as ratio of its characteristic value to characteristic time, dy/dτ ≈ y/τ the similar approximation can be also used for spatial derivatives).
 
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Can you write down the relevant Maxwell equation, then change all derivatives in length and time to simple division by their charactersitic values?
 
I believe I can use the following relation:
Equation: curl of B equals mu0 times j plus epsilon0 mu0 times the partial derivative of E with respect to t, the Ampère-Maxwell law in vacuum.



Defining the current density of J as the displacement current, by differentiating D with respect to time
Equation D = ε0 E + P, where D is the electric displacement field, ε0 the vacuum permittivity, E the electric field and P the polarization.



(dD/dt)We get:
Equation J_D = ε0 ∂E/∂t + ∂P/∂t, the displacement current density expressed as the time derivative of the electric field times vacuum permittivity plus the time derivative of polarization.



With B and E being defined as:
Equation: nabla dot B = 0, the differential form of Gauss's law for magnetism stating that the divergence of the magnetic field B is zero.

Maxwell-Faraday equation: curl of E equals negative partial derivative of B with respect to time, written as ∇ × E = −∂B/∂t.



So instead of differentiating to time I can now simply divide by time? However, I don't quite see where light speed comes in and how I could prove the displacement current actually being neglectable.
 
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