Displacement current in Maxwell equations

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SUMMARY

The discussion focuses on the conditions under which the displacement current in Maxwell's equations can be neglected, specifically when the characteristic time τ of the changing electromagnetic field satisfies τ >> L/c, where L is the system's characteristic size and c is the speed of light. Participants suggest using the approximation of time derivatives as ratios of characteristic values to characteristic time, specifically dy/dτ ≈ y/τ. The relevant Maxwell equation involves differentiating the electric displacement field D with respect to time to define the current density J. The challenge lies in incorporating the speed of light into the proof of the displacement current's negligible effect.

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Does anyone know how to solve or at least how to begin solving the following problem?:

Prove that displacement current in the Maxwell equations can be neglected if characteristic time τ of changing electromagnetic field in the system satisfies to the following condition: τ >> L/c where L is the characteristic size of this system and c is light speed. (Hint: time derivative of some variable y can be approximated as ratio of its characteristic value to characteristic time, dy/dτ ≈ y/τ the similar approximation can be also used for spatial derivatives).
 
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Can you write down the relevant Maxwell equation, then change all derivatives in length and time to simple division by their charactersitic values?
 
I believe I can use the following relation:
img981.png



Defining the current density of J as the displacement current, by differentiating D with respect to time
ab93b5aac5ffa87badaa48f32c50715a.png



(dD/dt)We get:
8df256232f07aa711d287438280647be.png



With B and E being defined as:
57619c6a86c79e56ac806faf21502c90.png

9cab6787646062d6e658cd1e83ad468f.png



So instead of differentiating to time I can now simply divide by time? However, I don't quite see where light speed comes in and how I could prove the displacement current actually being neglectable.
 
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