Displacement current in Maxwell equations

snyski
Messages
2
Reaction score
0
Does anyone know how to solve or at least how to begin solving the following problem?:

Prove that displacement current in the Maxwell equations can be neglected if characteristic time τ of changing electromagnetic field in the system satisfies to the following condition: τ >> L/c where L is the characteristic size of this system and c is light speed. (Hint: time derivative of some variable y can be approximated as ratio of its characteristic value to characteristic time, dy/dτ ≈ y/τ the similar approximation can be also used for spatial derivatives).
 
Last edited:
Physics news on Phys.org
Can you write down the relevant Maxwell equation, then change all derivatives in length and time to simple division by their charactersitic values?
 
I believe I can use the following relation:
img981.png



Defining the current density of J as the displacement current, by differentiating D with respect to time
ab93b5aac5ffa87badaa48f32c50715a.png



(dD/dt)We get:
8df256232f07aa711d287438280647be.png



With B and E being defined as:
57619c6a86c79e56ac806faf21502c90.png

9cab6787646062d6e658cd1e83ad468f.png



So instead of differentiating to time I can now simply divide by time? However, I don't quite see where light speed comes in and how I could prove the displacement current actually being neglectable.
 
Last edited by a moderator:
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
Back
Top