Distance between two layers in FCC unit cell

AI Thread Summary
The discussion centers on the geometric relationship between layers in a face-centered cubic (FCC) unit cell, specifically addressing the distance between these layers. The initial confusion arises from the assertion that this distance is a/√3, where 'a' is the edge length of the unit cell, versus the belief that it should be a/2 based on the proximity of face-centered atoms to surrounding edges. Participants clarify that the distance a/√3 pertains to the spacing between planes parallel to the (111) Miller indices, which represent planes of higher atomic density rather than the nearest planes. The conversation emphasizes the importance of selecting the correct planes when calculating distances, as different planes can yield varying measurements. The discussion concludes with a recognition of the significance of Miller indices in understanding crystal structures.
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How is the distance between any two layers in a FCC unit cell equal to a/√3, where a is the edge length? I think it should be a/2 because the distance of a face centered atom from any 4 edges surrounding it is a/2. Can someone explain it geometrically?
 
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Abdul Quadeer said:
How is the distance between any two layers in a FCC unit cell equal to a/√3, where a is the edge length? I think it should be a/2 because the distance of a face centered atom from any 4 edges surrounding it is a/2. Can someone explain it geometrically?

Divide the area density of atoms within a plane by the volume density of atoms in the crystal. This gives the distance between the chosen plane and the nearest parallel plane.

Of course, this still means you need to decide which planes you're measuring the distance between.
 
PhaseShifter said:
Divide the area density of atoms within a plane by the volume density of atoms in the crystal. This gives the distance between the chosen plane and the nearest parallel plane.

Going that way I got a/2.

PhaseShifter said:
Of course, this still means you need to decide which planes you're measuring the distance between.

a/√3 is the distance between which two planes in a fcc unit cell? Not the nearest ones?
 
Abdul Quadeer said:
a/√3 is the distance between which two planes in a fcc unit cell? Not the nearest ones?

Generally you'll be interested in the planes of greatest density rather than the closest planes. In fact, you can find planes arbitrarily close together, if you pick planes with a very low density.
 
That does not answer my question. a/√3 is the distance between which two planes in a fcc unit cell?
(btw I found this distance in the derivation of the height of a hexagonal unit cell)
 
It's the distance between planes parallel to the (111) plane.
 
(111) = ? :confused:
 
I learned something new there :smile:
Thanks!
 
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