Distance from a point to a plane

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SUMMARY

The closest point from the origin to the plane defined by the equation ax + by + cz = d is given by the coordinates P(ad/D², bd/D², cd/D²), where D² = a² + b² + c². The vector (a, b, c) is perpendicular to the plane, and the intersection of the line defined by the parametric equations (at, bt, ct) with the plane yields the required point. To find this point, one must calculate the distance after determining the value of t.

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I am trying to show that the point in the plane ax+by+cz=d closest to the origin is
P(ad/D^2, bd/D^2, cd/D^2) where D^2=a^2 + b^2 + c^2. How do I approach this? I tried using partial derivatives but got too complex after a while. Thanks
 
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The vector (a,b,c) is perpendicular to the plane. Therefore the line given by parametric form (at,bt,ct) passes through the origin and intersects the plane at the point closest to the origin. Simply calculate the distance after finding t.
 

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