A different interpretation of your question:
For what distribution is the distributional derivative the same as the elementary derivative of a given function?
Observe that in the above formula for the distributional derivative, if the mapping f is linear, then T is the same as f. (The elementary calculus analog is: if the function is linear, f(t) = at for some number a, then the derivative is a.)
In particular, the derivative operator d/dt is a linear mapping defined on spaces of differentiable functions. So the distributional derivative of the derivative operator, acting on a function g, is the derivative of g. In this sense, the derivative operator is the only mapping with this property.
This is hard to grasp, I know. It took me a long time, and lots of work.
The main issues are:
1) the distributional derivative acts on operators on the function space.
2) there are an awful lot of operators on function spaces in common use, and the standard notations for them is very scattered. I mentioned differential operators, but there are also pointwise multiplication, convolution, inner product, integral operators (these are all linear ones!) and then you get into the nonlinear ones... such as multiplying a function by itself pointwise etc etc. It's hard ot devise a consistent notation.