Divergence/Convergency of a series

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Homework Help Overview

The discussion revolves around testing the convergence or divergence of the series Ʃ1000(3/4)^n - n/(n+10000) from n=1 to ∞. Participants explore the behavior of the series components, particularly focusing on the geometric series and the rational function.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to analyze the series by separating its components, initially believing that the convergence of one part would imply the convergence of the whole. They question the validity of their approach after receiving conflicting information from a computational tool.

Discussion Status

Participants are actively engaging with the original poster's reasoning, providing insights into the properties of convergent and divergent series. There is a recognition that the sum of a convergent series and a divergent series results in divergence, although there is no explicit consensus on the original poster's understanding of the limit test.

Contextual Notes

Some participants note that the term n/(n+10000) does not converge, raising questions about the assumptions made regarding the series' behavior. The discussion also touches on the limitations of the root test in this context.

Heaviplace
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Homework Statement



I have to test this series for convergency/divergency

Ʃ1000(3/4)^n - n/(n+10000)

n=1 to ∞

The Attempt at a Solution



At first I thought of analyzing both parts separately, (3/4)^n is a geometric series with r < 1 and so it converges, and applying the root test to n/(n+10000). Then I'd have the sum of two convergent series that ofc, also converges.

Went to test my hypothesis on WolframAlpha, and it actually told me the series diverges by the limit test, which I verified to be true.

So my question is, why was the method I used, wrong?

Thanks in advance!
 
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n/(n+10000) doesn't converge by the root test. It doesn't converge at all. It doesn't even approach zero!
 
Indeed, you are right!

But that still leaves me the problem, but this time with the sum of a convergent series and divergent series =/
 
Heaviplace said:
Indeed, you are right!

But that still leaves me the problem, but this time with the sum of a convergent series and divergent series =/

The sum of a convergent series and a divergent series always diverges. Think of the partial sums.
 
Ok, see if I got it right, since one of the series does not converge, I can't bring up the property of the sum of two convergent series.

And even though (3/4)^n is convergent, the limit test shows that the sum of both series (<>0) is not.
 
Thanks really man, you really cleared things up for me.

Just a last question a bit off topic, where's the edit button? =P
 
Heaviplace said:
Ok, see if I got it right, since one of the series does not converge, I can't bring up the property of the sum of two convergent series.

And even though (3/4)^n is convergent, the limit test shows that the sum of both series (<>0) is not.

Sure, you can think of it that way. (3/4)^n approaches zero as n->infinity. n/(n+10000) doesn't. So the sum doesn't approach zero. Doesn't converge by the limit test.
 
Heaviplace said:
Thanks really man, you really cleared things up for me.

Just a last question a bit off topic, where's the edit button? =P

The 'Edit' button has been coming and going lately. No idea why.
 

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