Divergent Series: Finding the Largest Value of n

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    Divergent Series
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To determine the largest value of n for which the series $$\sum_{k=1}^\infty\frac{1}{k^n}$$ diverges, the integral test can be applied. The harmonic series, occurring at n = 1, is a well-known example of divergence. For values of n greater than 1, the series converges. Therefore, the largest value of n for divergence is 1. Understanding this relationship is crucial for analyzing the behavior of p-series.
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Hi all, is there any way to find what the largest value of n is such that $$\sum_{k=1}^\infty\frac{1}{k^n}$$ is divergent? I don't need an answer, I need an approach to the problem.
 
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eddybob123 said:
Hi all, is there any way to find what the largest value of n is such that $$\sum_{k=1}^\infty\frac{1}{k^n}$$ is divergent? I don't need an answer, I need an approach to the problem.

Integral test.

It is well known that if n = 1, the series is the harmonic series, which diverges.
 
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