The discussion revolves around a problem involving diverging and converging lenses, specifically focusing on finding the final position and size of an image formed by a lens system. The participants are exploring the application of the lens formula and the implications of virtual images in their calculations.
The discussion is active, with participants seeking clarification on the placement of images relative to the lenses and how to approach the calculations for the final image size. Some guidance has been offered regarding the consideration of lenses together versus separately, but there is no explicit consensus on the best approach yet.
Participants are navigating the complexities of lens systems, including the definitions of object and image distances, and the nature of virtual images. There is an emphasis on understanding the setup and assumptions made in the problem statement.
That's what I'm having trouble determining; what do I use for "do" in my second calculation?mfb said:
if di1 = -20cm, doesn't that place it behind the concave lens?mfb said:
If I had to guess I'd say to the right of Lens 2mfb said:
Again, this is the piece I do not understand.DrewHizzy said:
I answered Part A correctly with 9.6cm, hi/ho = di/do for part B? Do I make two calculations like Part A?mfb said: