Divide by one digit numbers by two digit numbers, and add to get 1

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The discussion revolves around solving a cryptarithmetic equation where letters represent different decimal digits from 1 to 9. The equation is A/(BC) + D/(EF) + G/(HI) = 1, with BC, EF, and HI being two-digit integers. Participants share their attempts at finding a solution, with one user expressing frustration after initially being close to the correct answer but ultimately resorting to looking up the solution. The problem is acknowledged as challenging yet engaging.
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Substitute each of the letters by a different decimal digit from 1 to 9 to satisfy this cryptarithmetic equation:

A/(BC) + D/(EF) + G/(HI) = 1

where, each of BC, EF and HI represents a two digit positive integer.
 
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This is my answer! [edit and its wrong]
8/16 + 9/27 + 5/30 damn just realized you can't have "0"

after 15 mins i cannot find a solution, and am starting to believe there isn't one!
 
Last edited:
phlegmy said:
after 15 mins i cannot find a solution, and am starting to believe there isn't one!

It's possible, but it ain't pretty. As in, 2 of the fractions you'll need aren't reducible to common things like 1/3 or 1/8, etc. The other fraction's pretty normal.

DaveE
 
oh man... i was pretty close to getting this right... i was on the right track at least.. but then i got pissed and looked it up instead.. good problem!
 
I got this one:
5/34 + 7/68 + 9/12
:smile:
 

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