Dividing Exponential Functions

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Discussion Overview

The discussion revolves around the process of dividing two exponential functions, specifically in the form A*e^(Cx) + B. Participants explore methods to simplify this division and seek relationships between different attributes represented by the functions.

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant inquires about the method for dividing two exponential functions and expresses a need to solve for a constant k.
  • Another participant notes that simplification is typically challenging when there is a sum in the denominator.
  • A different participant suggests a method involving substitution (e^x = y) to simplify the division, but acknowledges that the outcome may not align with the original intent.
  • A participant expresses uncertainty about the applicability of the proposed method and mentions attempting to linearize the functions using natural logarithms, but encounters difficulties due to logarithmic rules.
  • The participant clarifies that the functions represent different attributes of a system and seeks to establish a relationship between the variables n and v.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the best method for dividing the functions, and multiple approaches and uncertainties remain in the discussion.

Contextual Notes

Limitations include unresolved mathematical steps related to the division of exponential functions and the application of logarithmic rules, which complicate the linearization process.

impendingChaos
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How would one go about dividing two exponential functions.
Basically I have f(x)=k*g(x)
So to solve for k, k=f(x)/g(x)
How would one accomplish this when the functions are both within the format:
A*e^(Cx)+B

Thanks
 
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There's usually no nice simplification when there's a sum in the denominator.
 
There is a way to simplify, but it's not necessarily what you are looking for. You might or might not end up with an invariant remainder. Here:

\frac{Ae^{Cx} + B}{Oe^{Px} + Q}

For example, let's say A = 1 and P = 1\frac{Ae^{x} + B}{Oe^{x} + Q}

Make the substitution e^x = y and get

\frac{Ay + B}{Oy + Q}

Now we can write

\frac{A/O(Oy + Q - Q) + B}{Oy + Q}

\frac{A/O(Oy + Q ) - QA/O + B}{Oy + Q}

A/O + \frac{B - QA/O}{Oy + Q}

B - QA/O is the remainder here.
 
Last edited:
Hmm I will try your method Werg but like you say I am not sure it is what I am looking for.
I am also trying to make both individual functions into linear expressions by taking the natural log of both sides however I run into natrual log rules which keep this from succeeding. Any ideas in the department?
Another note, I would like to clarify that I should have represented the functions as something like:
f(n)
g(v)
they are both describing different attributes of a system. What I am trying to accomplish is finding a relationship between n and v. Still working towards a solution so any help greatly appreciated.

C.N.
 

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