Do sound waves affect the distance between protons in an atom?

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Sound waves do not have the capability to affect the distance between protons in an atom due to the immense forces required to influence nuclear structure, which far exceed what sound can transmit. The discussion highlights that atomic vibrations caused by sound are negligible compared to the strong nuclear forces at play, making the idea of sound-induced proton repulsion unrealistic. Virtual particles like pions and W+ bosons are not real entities that can be counted or measured in this context. The forces generated by sound waves are vastly weaker than those within atomic nuclei, rendering any effect on proton spacing insignificant. Overall, the interaction of sound with atomic structure is fundamentally limited and does not lead to the proposed phenomena.
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When an atom vibrates more than usual, say for example effected by a sound wave, do it's protons repel each other further apart than normal? Thus more charged virtual Pions occurring and decaying (discombobulating) into virtual W+ bosons?

Edit: I know that accelerated charged particles create a magnetic field but I don't want to assume things.
 
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There is no sound strong enough to influence the internal structure of nuclei. The materials simply cannot transmit the massive forces needed for that. You would completely evaporate and ionize your sample in the attempt.
HawkI said:
Thus more charged virtual Pions occurring and decaying (discombobulating) into virtual W+ bosons?
Virtual particles are not real. You cannot count them.
 
atomic vibration is natural, if say I plucked a Guitar string it would oscilate very fast, the atoms moving faster bumping the atoms around it which would continue into a pressure wave

Pions bring protons together, when protons come further apart they become charged pions to make up for the distance

protons repell each other, the more protons move the more of a magnetic field they create

the guitar string is made up of atoms so the protons in each atom would be moving more

in this example would there be more not real charged pions? thankyou for the responce so far i will try harder in future to make my questions clearer
 
There are no real pions at all.

The scales are completely different. It's like trying to rip apart a solid object by standing next to it and hoping that the own gravitational attraction will split it. It won't.
Let's say the guitar string oscillates by 1cm with 1 kHz. That makes 200 km/s^2 peak acceleration, or a force of 3*10-22 N on a single proton to follow that motion. This has to be compared with typical energies of 10 MeV and typical distances of 1 fm in a nucleus, which gives a typical force of about 1kN. The oscillation is 23 orders of magnitude weaker than the forces inside a nucleus. A factor of 100000000000000000000000!
Actually, trying to rip a solid object apart by standing next to it is much more "realistic", just ~15 orders of magnitude.
 
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Hey that's some interesting stuff right there, I'm not trying to rip apart, evaporate or ionize atoms here. I looked into sound energy and it's kinetic. The more the Earth spins, the more the lava inside moves thus more magnetic fields, that's what I mean by protons moving.

And thank you again mfb you have answered my question :)
 
You have the wrong model of the atom in your mind ...
 
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