Do We Include the Liquid State When Finding K?

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When determining K, the liquid state should be included in the calculations. While solid states are not considered, the activities of liquids in reactions are relevant. In many aqueous reactions, the activities can be approximated as 1 and may be disregarded. For near ideal liquid-liquid solutions or immiscible mixtures, the molar concentration can replace the activity. Including the liquid state is essential for accurate equilibrium calculations.
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when finding K, do we include the liquid state? I know the solid state is not included
 
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It would help if you provide an example with your question.

If I'm interpreting it correctly, then the answer is yes. Strictly speaking, we need to account for activities of liquids in the reaction, but in certain cases, the activities are close to 1 (most any aqueous reaction) and may be ignored. When dealing with near ideal liquid-liquid solutions or with mixtures of immiscible liquids, the actual molar concentration of the liquid may be used in the place of its activity (the same substitution that is made for most solutes in dilute solutions).
 

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