Do you just multiply the Yield strength by the thickness?

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Discussion Overview

The discussion revolves around the interpretation and application of yield strength in materials, particularly in relation to thickness and load capacity. Participants explore the implications of yield strength in practical scenarios, such as plates and pipes, and how it relates to internal stress and external loads.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant questions whether multiplying yield strength by thickness provides the maximum allowable force on a plate, suggesting a calculation of 10,650N based on given dimensions.
  • Another participant counters that multiplying yield strength (N/mm²) by thickness (mm) results in units of N/mm, which does not represent force, indicating a misunderstanding of the concept.
  • A participant seeks clarification on how to determine the load capacity in relation to yield strength.
  • Another participant questions if a thicker pipe with the same outer diameter has double the yield strength of a thinner pipe, probing the relationship between yield strength and thickness.
  • One participant explains that yield strength is an internal stress value and emphasizes that it does not directly correlate with the external load applied, regardless of thickness.
  • Another participant introduces concepts related to material behavior under stress, including elastic and plastic deformation, and mentions the influence of temperature on material properties.

Areas of Agreement / Disagreement

Participants express differing views on the relationship between yield strength and thickness, with some asserting that yield strength is an internal measurement not directly tied to external loads, while others seek to clarify this relationship. The discussion remains unresolved regarding the correct interpretation and application of yield strength in practical scenarios.

Contextual Notes

Participants highlight the importance of understanding internal versus external stresses and the limitations of applying yield strength directly to load calculations without considering additional factors such as safety and material behavior.

garygooboo
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The term yield strength is always bugging me deciphering the actual use in some cases. If I had a plate 3m x 2m 30mm material of Yield Strength 355N/mm², does this mean the maximum allowable force at one point on the plate is 10,650N (355 x 30mm), not taking into account safety factors, deflection, moments etc.

Do you just multiply the Yield strength by the thickness?
 
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In general, no. Just look at the units of stress: N/mm^2. If you multiply yield stress by thickness, you will be left with units of N/mm, which is not the units of force.
 
how do you tell how much load it can take then in relation to yield strength.
 
i don't think i am asking the question correctly. In other words what I mean is, say for instance you had a pipe of 355 MPa Yield Strength. If two pipes had the same outer diameter but one was 1 inch thick and the other 2 inches thick, does the 2 inch thick pipe have double the yield strength of the 1 inch pipe? Is there a relationship between yield strength and thickness?
 
Gary, you are not grasping the concept correctly. The yield strength of the material is actually an internal stress value in N/mm², usually gained from a tensile test. This doesn't mean if you apply a load i.e. 355 N then this will be fine for every mm of thickness you have.
The yield strength is a measurment of the internal stress at which the material will start to yield, not the external load you can apply. No matter how thick your material is and the amount of Pressure/load you apply to it, you can't have an internal stress value over 355 N/mm2 for any thickness (excluding safety factors etc).

The internal stresses will be less the thicker your material is, assuming the load is constant.
 
The questions you ask are properly solved by studying strength of materials.
 
Many materials, such as metals, react to stress as if they are a very stiff spring. Compressve stress will shorten the material in the axis of the stress while bulging in the other axes. Tensile stress will stretch the material and thin it elswhere. When the stress is removed the material will spring back to the original size and dimensions. The spring rate is sometimes called Young's Modulus.

Now, if the stress per cross section exceeds than the yield stength, the material does not spring back all the way if the stress is removed. It has yielded. Materials that have a yield strength much lower than their ultimate tensile strength are said to behave in a plastic manner. Those materials with a yield strength only a few percent lower than the ultimate tensile strength behave in a brittle manner. These behaviors may change for one particular material as temperature changes, also. It may sag of its own weight at high temperature and shatter in freezing temperatures.
 
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