Does a high emf excite electrons?

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A high electromotive force (emf) does not directly excite electrons to higher energy levels in a material like lithium. While the n = 2 energy level of lithium is 108.8 eV above the n = 1 level, an emf of 108.8 V in a DC circuit does not equate to this energy transfer. An electron volt measures energy, not electric potential, meaning voltage alone cannot excite electrons in this context. In solid lithium, outer electrons behave differently than in isolated atoms, forming a 'pool' that contributes to atomic bonding and electrical conduction. Therefore, the conduction process involves closely spaced energy levels rather than discrete atomic transitions.
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The n = 2 energy level of lithium is 108.8 eV away from the n = 1 energy level. Does that mean, in a DC circuit, that if you put an emf of 108.8 V along a lithium wire, that the high voltage will excite an electron to the n = 2 level?
 
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Nope, an electron volt is a unit of energy, not of electric potential (voltage).
 
In solid lithium, the energy levels of the 'outer' electrons are quite different from what they are in a lithium atom. In the solid these electrons are 'pooled' and lose their allegiance to particular atoms. These pooled electrons are responsible for the bonding of the atoms, and for the conduction of electricity. Their energy levels form bands of extremely closely spaced levels.
 
It may be shown from the equations of electromagnetism, by James Clerk Maxwell in the 1860’s, that the speed of light in the vacuum of free space is related to electric permittivity (ϵ) and magnetic permeability (μ) by the equation: c=1/√( μ ϵ ) . This value is a constant for the vacuum of free space and is independent of the motion of the observer. It was this fact, in part, that led Albert Einstein to Special Relativity.
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