Does a massive object interact with its own gravitational field?

In summary: What I meant was, if perturbation theory is only an approximation, and the necessary consequence of perturbation is self energy, then, would this thing called self energy be only a mere theoretical flaw due to this approximation, and does not exist in nature? Yes,the connected Green functions in any perturbative theory are just the propagators, and they are not really connected. There is no hidden paths in these Green functions.
  • #1
touqra
287
0
Does an electrically charged particle's own electric field affect its own path in space? i.e., does the particle's electrical nature interact with its own field?

Does a massive object interact with its own gravitational field?
 
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  • #2
touqra said:
Does an electrically charged particle's own electric field affect its own path in space? i.e., does the particle's electrical nature interact with its own field?

yes, a charged particle interacts with its own field and this is called the self energy. Indeed, this self energy has an influence on possible trajectories of this particle. Keep in mind that in field theory, the trajectory of a particle between two points, really is the "superposition" over all possible trajectories between those two points. You know, the Path-integral formalism...

Does a massive object interact with its own gravitational field?

A massive object curves space time, that is all there is to it according to general relativity.

regards
marlon
 
  • #3
Why is it that you have self energy for electromagnetism but not for gravitational force?

Both electromagnetism and gravity use the field concept. And both is pretty much anologous to the other, from the view of a single particle.
 
  • #4
touqra said:
Why is it that you have self energy for electromagnetism but not for gravitational force?

Both electromagnetism and gravity use the field concept. And both is pretty much anologous to the other, from the view of a single particle.

Self energy does not come from EM, it comes from QED ! This is the quantummechanical approach to EM-phenomena. Self energy arises when you are working with perturbation theory and this is an approximative way to solve a Schrodinger equation. This way of working, however does not apply for general relativity. The fields in QED are quantum-fields, those in GTR are NOT. General Relativity and GTR are totally different in nature because of the Heisenberg uncertainty and the superposition principle for example. You don't have those in GTR

marlon
 
  • #5
marlon said:
Self energy does not come from EM, it comes from QED ! This is the quantummechanical approach to EM-phenomena. Self energy arises when you are working with perturbation theory and this is an approximative way to solve a Schrodinger equation. marlon

So is there the existence of self energy in the theory for strong force, ie, in QCD?

marlon said:
Self energy arises when you are working with perturbation theory and this is an approximative way to solve a Schrodinger equation.
marlon

If perturbation theory is only an approximative way to solve the Schrodinger
equation, would the concept of self energy be actually an illusion, if we have the exact way of solving the Schrodinger equation?

marlon said:
This way of working, however does not apply for general relativity. The fields in QED are quantum-fields, those in GTR are NOT. General Relativity and GTR are totally different in nature because of the Heisenberg uncertainty and the superposition principle for example. You don't have those in GTR
marlon


Wouldn't a good theory of gravity should also have this concept of self energy? since it is also a force, and should be equivalent to the EM force.
 
  • #6
touqra said:
So is there the existence of self energy in the theory for strong force, ie, in QCD?

Yes,in the SM at least,every QFT has self-energy terms in its (non necessarily convergent) perturbation series.Of course,Quantum Chromodynamics cannot make an exception.



touqra said:
If perturbation theory is only an approximative way to solve the Schrodinger
equation, would the concept of self energy be actually an illusion, if we have the exact way of solving the Schrodinger equation?

How would that happen?Please,give an example of an INTERACTING quantum field theory (i put the word "interacting" explicitely just to make sure you wouldn't cheat and come up with a free theory,which is very "solvable" and whose connected Green functions are only the propagators :wink: ).




toukra said:
Wouldn't a good theory of gravity should also have this concept of self energy? since it is also a force, and should be equivalent to the EM force.

Yes,all known (to have failed due to nonrenormalization (e.g. HE) or incapability to produce Newton's equations in the classical limit (e.g.Weyl gravity)) quantum gravity theories have self-energy diagrams for the graviton.As you have been told already,it's a pure QM effect.

Daniel.
 
  • #7
dextercioby said:
How would that happen?Please,give an example of an INTERACTING quantum field theory (i put the word "interacting" explicitely just to make sure you wouldn't cheat and come up with a free theory,which is very "solvable" and whose connected Green functions are only the propagators :wink: ).

Daniel.

What I meant was, if perturbation theory is only an approximation, and the necessary consequence of perturbation is self energy, then, would this thing called self energy is only a mere theoretical flaw due to this approximation, and does not exist in nature?

What do you mean by "solvable" and that the connected Green functions are only the propagators?
 
  • #8
touqra said:
What I meant was, if perturbation theory is only an approximation, and the necessary consequence of perturbation is self energy, then, would this thing called self energy is only a mere theoretical flaw due to this approximation, and does not exist in nature?


We have no experimental evidence so far which would claim the the perturbation series for any of the QFT-s involved in the SM (renormalizable theories) would lead to catastrophic results...There's a problem with the QCD (the strong interaction has a large coupling constant,which is non suitable with our classic idea of perturbative expansion (c QM textbooks)),but nontheless,we have no doubt regarding the correctness of self-energy of quarks or gluons for example...

touqra said:
What do you mean by "solvable" and that the connected Green functions are only the propagators?

I mean that in the operator approach to QFT,one has to solve the classical field equations b4 passing onto quantization.That's what i meant by "solvable".It doesn't apply to Yang-Mills fields (which are not really free,but self-interacting,just like the gravitational field).
Yes,for a FREE theory,the Connected Green Functions are only the propagators.

Daniel.
 
  • #9
With gravity the self-energy problem is subtle and not quite understood, outside of weak field approximations. General gravitons (by that I mean those that are output by the *real* theory outside of the approximation) should not only have self energy graphs, but they presumably back-react with the actual metric that they themselves generate.

Its very tough to conceptualize, harder still to write down sensible equations for.

In the weak field case, there are various selfconsistency measures that are often imposed. In string theory these mechanisms can actually induce topology change.
 

1. What is a massive object?

A massive object is any object that has a large amount of mass. Mass is a fundamental property of matter that determines its resistance to acceleration and is responsible for creating and interacting with gravitational fields.

2. How does a massive object interact with its own gravitational field?

A massive object interacts with its own gravitational field through the force of gravity. The object's mass creates a gravitational field around it, and the field exerts a force on the object in all directions, including towards its own center of mass.

3. Does a massive object affect its surroundings through its gravitational field?

Yes, a massive object affects its surroundings through its gravitational field. The gravitational field extends infinitely in all directions, so any other objects within the field will experience the force of gravity from the massive object.

4. Can a massive object's gravitational field be stronger than its own gravity?

No, a massive object's own gravitational field cannot be stronger than its own gravity. The strength of a gravitational field depends on the mass of the object creating it, so a massive object's own gravity will always be stronger than its own field.

5. How does the size of a massive object affect its gravitational field?

The size of a massive object does not significantly affect its gravitational field. The strength of a gravitational field is determined by the mass of the object, not its size. However, the size of an object can affect the distance at which its gravitational field is felt by other objects.

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