Does an Electric Field Outside of a Wire Supply Energy to a Resistor?

Click For Summary
SUMMARY

The discussion centers on the concept of energy transfer in electrical circuits, specifically addressing the role of electric and magnetic fields. It establishes that while a DC circuit does not have an electric field outside the wire, it does possess a magnetic field. The Poynting vector is introduced as a means to represent the flow of power in electromagnetic waves, indicating that energy is contained within these fields. The Drude model is referenced to explain how electrons interact with resistors, converting energy into heat through collisions with the atomic lattice.

PREREQUISITES
  • Understanding of Poynting vector in electromagnetic theory
  • Familiarity with the Drude model of electrical conduction
  • Knowledge of AC and DC circuit behavior
  • Basic principles of electromagnetic fields
NEXT STEPS
  • Research the Poynting vector and its applications in circuit analysis
  • Study the Drude model and its implications for electron behavior in materials
  • Explore the differences between AC and DC circuits in terms of electromagnetic fields
  • Investigate the relationship between energy dissipation in resistors and heat generation
USEFUL FOR

Electrical engineers, physics students, and anyone interested in the principles of energy transfer in electrical circuits.

GrizzlyBat
Messages
36
Reaction score
0
Hey, my friend started asking questions about how energy works with circuits, and he linked me this page. I have never heard of poynting fields before.

The idea I find most interesting is where the "Electromagnetic energy flows out of the battery and into the empty space around the circuit". Is this implying that there is an electric field outside of the wire as well, and it is supplying energy to the resistor some how?
 
Physics news on Phys.org
Realistically, the energy is always contained in the fields and waves. Even in a DC circuit, we still have electromagnetic waves because every circuit has a point that it is turned on which prevents it from being truly DC. The Poynting vector is a vector the represents the flow of power of an electromagnetic wave. However, I have seen that you can make a similar treatment even of an idealized DC circuit. I believe that you can show that the fields of a DC current in (well, if it's an ideal conductor the currents are on, not in) the wire have the energy of the circuit. That is, you can show that the energy/power contained in the fields is the same as the ohmic energy, IV.

So the fields and waves contain the actual energy. This is transferred to devices by the fact that the fields induce currents in the wires/transmission lines. These currents are physical charges (electrons) and the charges interact with the circuit devices, causing energy to be dissipated. For a resistor, this is done by what is known as the Drude model. That is, the electrons move through the resistor and have a high rate of collisions with the lattice of atoms that make up the material. Each collision causes the lattice to vibrate which is heat energy. So the collisions of the charges bleed off energy from the fields that accelerate the charges into heat.

For a DC circuit, there is no electric field outside the wire, but there is a magnetic field. But any AC signal is going to have both electric and magnetic fields in an electromagnetic wave.
 

Similar threads

  • · Replies 16 ·
Replies
16
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 30 ·
2
Replies
30
Views
4K
  • · Replies 16 ·
Replies
16
Views
5K
  • · Replies 21 ·
Replies
21
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 100 ·
4
Replies
100
Views
11K
  • · Replies 38 ·
2
Replies
38
Views
6K
  • · Replies 2 ·
Replies
2
Views
1K