Does an Elliptic Orbit's Speed Depend on Its Semi-Major Axis?

  • Thread starter Thread starter fahd
  • Start date Start date
fahd
Messages
40
Reaction score
0
hi
i have this question to do which says..

*)A particle moves in a elliptic orbit under the influence of a central force F= -k/r^2.Prove that the product of the maximim and minimum speeds is equal to [2 pi a/t]^2 where 'a' is the semi major axis of the ellipse and 't' is the period of its motion..

Dont u think it should be the semi minor axis 'b' instead of the semi major axis 'a'..in the question..because I am getting the former as the right answer..
please help!
 
Physics news on Phys.org
wow. i have the exact same problem.
you can express the 'right answer' in terms of b
( \frac{2 \pi a} { \tau } )^2 eqs 1
recall:
\tau = \frac{2 A} {l} eqs 2
where A is the area of an ellipse and is given by ╥ab
substituting 2 into 1 gives:
( \frac{2 \pi a} { \tau } )^2 = \frac{l^2} {b^2}
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
Back
Top