Does Bulb Resistance Change with Different Current Levels?

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    Bulb Resistance
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SUMMARY

The resistance of an electric bulb can be calculated using Ohm's Law, represented by the equation V = IR, where V is voltage, I is current, and R is resistance. For a bulb drawing 2.4 amperes at 12.0 volts, the resistance is 5 ohms (R = V/I = 12V/2.4A). When the current drawn by the bulb decreases, its resistance does not remain constant; instead, it increases due to the temperature coefficient of the filament material, which affects resistance at different current levels. This phenomenon is linked to the concept of inrush current, which describes the initial surge of current when the bulb is first powered on.

PREREQUISITES
  • Understanding of Ohm's Law (V = IR)
  • Basic knowledge of electrical circuits
  • Familiarity with the concept of inrush current
  • Knowledge of the temperature coefficient of resistance
NEXT STEPS
  • Research the temperature coefficient of resistance in materials
  • Learn about inrush current and its effects on electrical components
  • Explore the relationship between current, voltage, and resistance in different types of bulbs
  • Study the impact of temperature on the resistance of conductive materials
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Electrical engineers, physics students, and anyone interested in understanding the behavior of electrical components under varying current conditions.

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Request answer for the below question:

"An Electric bulb draws 2.4 amphere at 12.0 volts. What is the resistance. What happens to the resistance of the same bulb when it draws current less than that of the given value?"


does the resistance decrease, increase or remain same? i was marked wrong for writing that it remains same. Please help
 
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For the second part look up "inrush current"
 
Are you familiar with the equation V = IR, where V is the voltage, I is the current, and R is the resistance? This is one of the most basic and used equations in electrical circuit theory.
 

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