Does Time Dilation Occur with Uniform Motion?

  • Thread starter Thread starter fred2028
  • Start date Start date
  • Tags Tags
    Change
fred2028
Messages
19
Reaction score
0
Assume I am traveling in a spaceship at 0.9c towards a certain star, away from Earth. Then, some guy on Earth shines a really bright LASER light at the same star, causing a beam right beside my ship, so that the light and my ship travel in parallel paths. Because I am traveling at 0.9c, I should see that LASER to be going at 0.1c right? But, when I am moving, the time interval should be smaller (to get from one place to another). Say that The LASER took 1 second to travel 3x10^8 meters. To me, would it be going faster, since less than 1 second has passed for me while it traveled the same distance?

v = d/t

Since t is smaller because I'm moving at 0.9c, v becomes bigger. Would c be bigger in my moving frame of reference?
Also, does time slow down only when you accelerate or when you travel with uniform motion also?
 
Physics news on Phys.org
fred2028 said:
Assume I am traveling in a spaceship at 0.9c towards a certain star, away from Earth. Then, some guy on Earth shines a really bright LASER light at the same star, causing a beam right beside my ship, so that the light and my ship travel in parallel paths. Because I am traveling at 0.9c, I should see that LASER to be going at 0.1c right?
No, velocities don't add that way in relativity. You have to use the formula for relativistic velocity addition, which says that if A is traveling at speed v relative to B, and B is traveling at speed u relative to C, then A's speed relative to C is (v + u)/(1 + u*v/c^2). In this case, if A is the light beam and B is the Earth, so v=1c, then if C is your ship, so u=-0.9c (negative because in your frame the Earth is moving in the opposite direction as the light beam is moving in the Earth's frame), then you will measure the velocity of the light beam as (1c - 0.9c)/(1 - 1*0.9) = 0.1c/0.1 = 1c. It is in fact one of the fundamental postulates of relativity that each observer should measure light to move at the same speed in his own rest frame.
fred2028 said:
But, when I am moving, the time interval should be smaller (to get from one place to another). Say that The LASER took 1 second to travel 3x10^8 meters. To me, would it be going faster, since less than 1 second has passed for me while it traveled the same distance?

v = d/t

Since t is smaller because I'm moving at 0.9c, v becomes bigger. Would c be bigger in my moving frame of reference?
To understand why each observer measures a light beam to move at c, you must take into account the fact that each observer sees a moving observer's rulers to be shrunk, their clocks to be slowed down, and their clocks to be out-of-sync with one another. I gave an example showing how all these factors together ensure they both measure the light's speed to be c in post #6 from this thread.
fred2028 said:
Also, does time slow down only when you accelerate or when you travel with uniform motion also?
Keep in mind that there's no "objective" truth about whose clocks slow down--each observer measures the other one's clocks to run slower than their own. However, from the perspective of a given observer, a moving clock will always be slowed down regardless of whether it's accelerating or moving inertially; at any given instant, if its instantaneous velocity is v, its rate of ticking at that instant is \sqrt{1 - v^2/c^2}.
 
Last edited:
...and always remember that when dealing with relativity and "modern physics", you sort of want to treat it like politics... take 90% of rational thinking and throw it out the window...

another suggestion...read the Mr. Tompkins book...
 
  • Like
Likes Chris Miller
dingpud said:
...and always remember that when dealing with relativity and "modern physics", you sort of want to treat it like politics... take 90% of rational thinking and throw it out the window...

another suggestion...read the Mr. Tompkins book...

Yes, read Mr. Tompkins in Wonderland, its a fun read.

HOWEVER, it is not rational thinking you need to throw out it is preconceived notions as to how you think it OUGHT to be. Rather then closing your eyes and dreaming, study the math and let the MATH guide you to the correct and rational conclusions.
 
yes you are right...

I must say, when I first began studying relativity, it was very odd... like you said, preconceptions on how things "are" from environmental influence vs. how they are after "proving them with math's" can be a totally different thing...

spacetime still gets me sometimes...
 
OK, so this has bugged me for a while about the equivalence principle and the black hole information paradox. If black holes "evaporate" via Hawking radiation, then they cannot exist forever. So, from my external perspective, watching the person fall in, they slow down, freeze, and redshift to "nothing," but never cross the event horizon. Does the equivalence principle say my perspective is valid? If it does, is it possible that that person really never crossed the event horizon? The...
From $$0 = \delta(g^{\alpha\mu}g_{\mu\nu}) = g^{\alpha\mu} \delta g_{\mu\nu} + g_{\mu\nu} \delta g^{\alpha\mu}$$ we have $$g^{\alpha\mu} \delta g_{\mu\nu} = -g_{\mu\nu} \delta g^{\alpha\mu} \,\, . $$ Multiply both sides by ##g_{\alpha\beta}## to get $$\delta g_{\beta\nu} = -g_{\alpha\beta} g_{\mu\nu} \delta g^{\alpha\mu} \qquad(*)$$ (This is Dirac's eq. (26.9) in "GTR".) On the other hand, the variation ##\delta g^{\alpha\mu} = \bar{g}^{\alpha\mu} - g^{\alpha\mu}## should be a tensor...
ASSUMPTIONS 1. Two identical clocks A and B in the same inertial frame are stationary relative to each other a fixed distance L apart. Time passes at the same rate for both. 2. Both clocks are able to send/receive light signals and to write/read the send/receive times into signals. 3. The speed of light is anisotropic. METHOD 1. At time t[A1] and time t[B1], clock A sends a light signal to clock B. The clock B time is unknown to A. 2. Clock B receives the signal from A at time t[B2] and...

Similar threads

Replies
15
Views
2K
Replies
11
Views
2K
Replies
35
Views
5K
Replies
10
Views
6K
Replies
5
Views
2K
Back
Top