Does electromagnetic radiation from pulsar stars

Chaos' lil bro Order
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Does electromagnetic radiation emitted by pulsars carry enough energy as to make the gravity created by these emissions significant enough to gravitationally effect distant objects many light years away? In other words, can a pulsar star or a neutron star, effect distant planets or even distant stars, by perturbing their orbits, but not from the gravity of the pulsar or neutron star itself, but from the gravity created by the actual EM emissions themselves, even light years away. My gut says the gravity is too little, even though if the Earth was in the beam's path it may cook off the atmosphere and us with it. Just out of curiosity, if you could idealize an experiment where a tank, a cubic meter is size, was filled with water and an identical tank was left empty with the challenge to you to fill the empty tank with radiation until the density was sufficiently equal as to cause the same amount of specific gravity as the water tank, how much would it be?
 
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The answer to your first question is "no". Your second question is poorly formed (what units are you looking for?), but the energy would be equal to mc2.
 
How about MeV.
 
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From $$0 = \delta(g^{\alpha\mu}g_{\mu\nu}) = g^{\alpha\mu} \delta g_{\mu\nu} + g_{\mu\nu} \delta g^{\alpha\mu}$$ we have $$g^{\alpha\mu} \delta g_{\mu\nu} = -g_{\mu\nu} \delta g^{\alpha\mu} \,\, . $$ Multiply both sides by ##g_{\alpha\beta}## to get $$\delta g_{\beta\nu} = -g_{\alpha\beta} g_{\mu\nu} \delta g^{\alpha\mu} \qquad(*)$$ (This is Dirac's eq. (26.9) in "GTR".) On the other hand, the variation ##\delta g^{\alpha\mu} = \bar{g}^{\alpha\mu} - g^{\alpha\mu}## should be a tensor...
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