Does light travel at the speed of light?

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Discussion Overview

The discussion revolves around the nature of light and its speed, particularly in the context of gravity and mass. Participants explore concepts related to the mass of photons, the effects of gravity on light, and the implications of black holes on light's behavior.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants propose that if light is affected by gravity, it must have some form of mass, leading to questions about its speed.
  • Others argue that light has no rest mass, and thus, according to the equation E = mc^2, it travels at the speed of light (c) regardless of its energy or frequency.
  • A participant mentions that light's frequency changes due to gravity, but its speed remains constant at c.
  • There is a discussion about how black holes interact with light, with some suggesting that light emitted near a black hole's event horizon may experience redshift and that its frequency approaches zero as it escapes.
  • One participant presents an analogy comparing light's behavior near a black hole to a ball rolling up a ramp, questioning if light behaves similarly when emitted close to the event horizon.

Areas of Agreement / Disagreement

Participants express differing views on whether light has mass and how gravity affects its speed and behavior. There is no consensus on these points, and the discussion remains unresolved.

Contextual Notes

Some claims depend on interpretations of mass and energy, and the discussion includes unresolved assumptions about the nature of light and gravity.

jbar18
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I can't figure out why it should. Here's what I'm thinking:

- Light is affected by the gravity, and gravity is the interaction between masses, so surely light must have mass in some form.

- Light has no mass, but has energy depending on the frequency of the photon. By E = mc^2, photons with higher frequency should have more mass, and therefore should surely move slower. I have heard of observations though from far out in space (can't remember any specifics, sorry) where two photons from the same event but of different frequencies will be detected at the same time, surely indicating that the energy of the photons does not affect the velocity.

- If light has mass, then surely it cannot travel at the true speed of light.

Can someone explain please?

Thank you
 
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If light had mass then no it wouldn't travel at c, but it doesn't. In E = mc^2 the m is rest mass and since light is never at rest m = 0.

The correct equation is E^2 = (pc)^2 + (mc^2)^2.

For light m = 0, so we use the pc bit which is momentum. Light is affected by gravity however but will change frequency not speed.
 
cosmik debris said:
If light had mass then no it wouldn't travel at c, but it doesn't. In E = mc^2 the m is rest mass and since light is never at rest m = 0.

The correct equation is E^2 = (pc)^2 + (mc^2)^2.

For light m = 0, so we use the pc bit which is momentum. Light is affected by gravity however but will change frequency not speed.

Thanks, that's a very clear answer. So if gravity only affects the frequency, how does, say, a black hole, pull light in? Would it squash the wavelength to 0, or even make it negative?
 
Remember, gravity is an interaction between anything with energy, not just mass. So photons still attract gravitationally.
 
jbar18 said:
how does, say, a black hole, pull light in?

The way that a gravitational sink (such as a black hole) affects light is not a counterpart of how matter is afffected.
If you fire a rocket upwards and it doesn't have enough velocity then gravity causes it to make a U-turn. That is a form of 'pulling in'. For light there is no such U-turn scenario. There is no such thing as slowing down light.

If the light is emitted outside the event horizon then the light will escape. There is an energy cost to traveling out of the gravitational sink. The closer to the event horizon the light was emitted, the stronger the redshift.

So, expressed mathematically, in the limit of emission arbitrarily close to the event horizon, you get for light having traveled out that the frequency goes to 0, and correspondingly the wavelength goes to infinitely long.About the statement: 'there is no such thing as slowing down light'. At every altitude above the black hole's event horizon you can measure the local speed of light, and it will always come out the same: c.
 
Here's a thought I had the other day on this while talking to my roomate.

If gravity is the bending of spacetime, then inside a black hole's event horizon all space is curved so that it all leads back to the black hole correct? If so, would light being emitted behind the event horizon be similar to something like rolling a ball up one side of a skateboard U ramp? The ball initially goes up, but it eventually reaches a point where the vertical velocity is zero and it only has some horizontal velocity (analogy to light losing energy before it falls back in a black hole), so it curves and comes back down the ramp.

Would light act this way at all? IE if a photon heads nearly straight up out of the black hole, its path in spacetime is curved in such a way that it simply gets turned right back around (kind of like the ball on the ramp, but it never slows down) and falls back in?
 
jbar18 said:
I can't figure out why it should. Here's what I'm thinking:

- Light is affected by the gravity, and gravity is the interaction between masses, so surely light must have mass in some form.

- Light has no mass, but has energy depending on the frequency of the photon. By E = mc^2, photons with higher frequency should have more mass, and therefore should surely move slower. I have heard of observations though from far out in space (can't remember any specifics, sorry) where two photons from the same event but of different frequencies will be detected at the same time, surely indicating that the energy of the photons does not affect the velocity.

- If light has mass, then surely it cannot travel at the true speed of light.

Can someone explain please?

Thank you

Please start by reading the PF FAQ thread in the General Physics forum.

Zz.
 

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