Does Light Travel Through Fiber Optic Cable Generate EMF?

AI Thread Summary
Light traveling through fiber optic cables does not generate a detectable electromagnetic field outside the fiber, except in cases where the fiber is damaged or excessive light causes infrared radiation. Photons, which carry light, do not behave like electrons in metal wires since they lack charge and mass, meaning they do not create external fields. The discussion clarifies that treating light as a wave and understanding its properties of reflection and refraction is sufficient for comprehension. The inquiry also touches on the curiosity about whether sea creatures, like sharks, can detect fiber optic cables, but this is not supported by the physics of light. Overall, the conversation emphasizes the fundamental differences between photons and electrons in terms of electromagnetic field generation.
Sayagain
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Does light traveling through a fiber optic cable generate any sort of detectable electromagnetic field? Please forgive the stupid question. It’s something that popped into mind recently and google hasn’t adequately answered for me. I’m not a scientist or physicist. :blushing:
 
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Light is an electromagnetic field.
Outside the fiber, not counting the ends of it: No, unless the fiber is broken (or unless you use so much light that it warms up and emits more infrared radiation).
 
Thanks. I was curious if photons traveling along fiber optics behaved like electrons tracking along a metal wire. I was thinking about undersea cables and started wondering if fiber optic cables would be detectable by sea creatures such as sharks. No particular reason, just something that popped into my head this evening. :biggrin:
 
Sayagain said:
Thanks. I was curious if photons traveling along fiber optics behaved like electrons tracking along a metal wire
forget photons
treating the light in the fibre with classical physics is all your need
treat the light as a wave with all the usual reflection and refraction properties
 
Sayagain said:
Thanks. I was curious if photons traveling along fiber optics behaved like electrons tracking along a metal wire.
There is no parallel here. Electrons have a charge and it is the moving charge that creates the external field. Photons have no charge (or mass) so they do not behave in the same way.
 
Thank you. It makes perfect sense to me now.
 
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