Does ln[ln(x)] = ln(x) * ln(x)

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The equation ln[ln(x)] does not equal ln(x) * ln(x). For example, when x = e, ln(e) * ln(e) equals 1, while ln(ln(e)) equals 0. This highlights the distinction between function composition and function multiplication. Further manipulation of the expressions shows that they yield different results, reinforcing that ln(ln(x)) and (ln(x))^2 are not equivalent. Understanding these differences clarifies why the two expressions cannot be considered equal.
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Homework Statement


Does ln[ln(x) = ln(x) times ln(x)?


Homework Equations




The Attempt at a Solution

 
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Well, no. Take x=e. ln(e)*ln(e)=1, ln(ln(e))=ln(1)=0.
 
And generally speaking, f(f(x)) is different from f(x)*f(x). It's the difference between function composition (evaluation a function of a function) and function multiplication.
 
Maybe if we manipulated the expression a little it will become clearer that each function is not equal to each other.

ln\left(ln(x)\right)=\left(ln(x)\right)^2

ln(x)=e^{\left(ln(x)\right)^2}

ln(x)=(e^{ln(x)})^{ln(x)}

ln(x)=x^{ln(x)}

Does it look more obvious now as to why these expressions are not equal?
 
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