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EnumaElish
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In view of the observational equivalence of gravity and acceleration, does acceleration produce ripples in spacetime, similar to gravity waves?
In view of the observational equivalence of gravity and acceleration, does acceleration produce ripples in spacetime, similar to gravity waves?
What I did not get here is that it is a mass that is accelerated. So wouldn't this cause tiny changes in spacetime and thus make a gravitational wave possible, even if it might not be measurable?In short, in both cases, the acceleration does not involve any change in the curvature of spacetime at all. And gravitational waves are changes in the curvature of spacetime that propagate at the speed of light. So if there is no change in the curvature of spacetime, there are no gravitational waves.
Are you asking about treating the rocket case using GR rather than SR? Then, yes, in general, an accelerating rocket would generate (undetectable) gravitational radiation. [There are special cases where it wouldn't, e.g. the Kinnersly photon rocket solution. However, if you perturb the thrust pattern at all on that solution, you will get GW.] Some of the GW would be attributable to the mass of of they rocket payload.What I did not get here is that it is a mass that is accelerated. So wouldn't this cause tiny changes in spacetime and thus make a gravitational wave possible, even if it might not be measurable?
it is a mass that is accelerated. So wouldn't this cause tiny changes in spacetime and thus make a gravitational wave possible, even if it might not be measurable?
If two black holes are rotating around each other at variable velocities (perhaps because of elliptical orbits), they would alternately be accelerating and decelarating.
Wherever that is the case, could a fraction of what is measured by Ligo be explained by the acceleration?
Thank you. I was just asking because I thought that although unbelievably small it might be a non-zero solution. (I admit it's not really of physical interest.)If we are talking about a mass that produces non-negligible spacetime curvature being accelerated, we are talking about a different situation than the OP was referring to. If we are talking about "gravity and acceleration being equivalent", we are talking about the Equivalence Principle, which only applies in a small local patch of spacetime in which curvature can be ignored. Also, strictly speaking, the EP only applies to "test objects", which are idealized objects that produce zero spacetime curvature themselves. That was the scenario I was assuming in my response to the OP.
I was just asking because I thought that although unbelievably small it might be a non-zero solution.
The absence of gravitational radiation in Kinnersley's ``photon rocket'' solution of Einstein's equations is clarified by studying the mathematically well-defined problem of point-like photon rockets in Minkowski space (i.e. massive particles emitting null fluid anisotropically and accelerating because of the recoil). We explicitly compute the (uniquely defined) [it]linearized[/it] retarded gravitational waves emitted by such objects, which are the coherent superposition of the gravitational waves generated by the motion of the massive point-like rocket and of those generated by the energy-momentum distribution of the photon fluid. In the special case (corresponding to Kinnersley's solution) where the anisotropy of the photon emission is purely dipolar we find that the gravitational wave amplitude generated by the energy-momentum of the photons exactly cancels the usual 1/r gravitational wave amplitude generated by the accelerated motion of the rocket. More general photon anisotropies would, however, generate genuine gravitational radiation at infinity. Our explicit calculations show the compatibility between the non-radiative character of Kinnersley's solution and the currently used gravitational wave generation formalisms based on post-Minkowskian perturbation theory.