Does ω^2 Equal v^2/r^2 or (v/r)^2 in Angular Velocity Calculations?

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Angular velocity ω is defined as linear velocity v divided by radius r, expressed as ω = v/r. When considering ω squared, both ω^2 = v^2/r^2 and ω^2 = (v/r)^2 are mathematically equivalent. The confusion arises from the interpretation of the equations, but they yield the same result dimensionally. The discussion highlights the importance of clarity in mathematical expressions, especially when solving problems outside of a classroom setting. Understanding these relationships is crucial for tackling related physics problems effectively.
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ok, if angual velocity ω = linear velocity v / radius r

therefore ω=v/r

but what if i have ω^2 ( to the power of 2 )

does ω^2=v^2/r^2

or does it eqaul ω^2=(v/r)^2

many thanks, this is really bugging me and preventing me solve a problem since I am not in class
 
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it's same. moreover, if you are getting confused check it dimensionally.
 


of course of course, thank you, gawd this is a hard problem I am working on, just making sure all the particulars are in the right place and where they should be as I am not managing to solve this at all, ill carry on though lol. thanks dude
 


acat said:
ok, if angual velocity ω = linear velocity v / radius r

therefore ω=v/r

but what if i have ω^2 ( to the power of 2 )

does ω^2=v^2/r^2

or does it eqaul ω^2=(v/r)^2

many thanks, this is really bugging me and preventing me solve a problem since I am not in class

They are the same.
 


Also this has nothing to do with "Linear and Abstract Algebra" so I am moving it to "General Math".
 
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