Does rotation of rigid body need a couple or only 1 force is sufficien

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SUMMARY

A single force can indeed cause a rigid body to both rotate and translate, provided that the force is applied off-center relative to the body's center of mass. The torque generated by the force, calculated as the cross product of the position vector (r) and the force vector (F), is non-zero when the force is applied at a distance from the center of mass. This results in angular momentum, leading to rotation. Practical examples, such as flicking a wooden scale or kicking a football off-center, illustrate this principle effectively.

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  • Understanding of torque and angular momentum
  • Familiarity with the concept of center of mass
  • Basic knowledge of vector mathematics
  • Experience with real-world physics applications, such as billiards or sports
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  • Conduct experiments demonstrating torque using a wooden scale and a smooth surface
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koolraj09
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Hi all,

Suppose we go in space where no gravity and friction exists. If there is a bar, in say - horizontal plane and we apply a force at one end of the bar, in this plane and perpendicular to the bar. Will that bar rotate and translate or it will only undergo pure translational motion without rotation?
In other words is it sufficient to apply a single force and cause a body to rotate? Or do we need to apply a couple/moment to make the body rotate.
 
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It will rotate and translate.
 
Can you please give me an elaborate explanation as why this is true?
 
If the force vector is F and the position of the point of application of that force is r (measured from the body's centre of mass), then the torque is r cross F. If you apply a force on the bar in the way you describe, r cross F is nonzero so the torque is nonzero, which means the object will gain angular momentum, i.e. begin to rotate.
 
Can only one single force provide this rotation (as well as translation) or we need some other force to produce this rotation?
 
koolraj09 said:
Can only one single force provide this rotation (as well as translation) or we need some other force to produce this rotation?

Yes, a single force can provide this, as long as r cross F is not zero.
 
Thanks guys. The explanation is obviously right. But I am still not convinced.
Can you suggest me some experiment in which I will be able to confirm/demonstrate this fact - the fact that a rigid body can rotate when only a single force acts on the whole body with no counter/opposing force present?
 
koolraj09 said:
Thanks guys. The explanation is obviously right. But I am still not convinced.
Can you suggest me some experiment in which I will be able to confirm/demonstrate this fact - the fact that a rigid body can rotate when only a single force acts on the whole body with no counter/opposing force present?

Have you ever played billiards/snooker/pool ? In the game if you hit the ball right in the middle ,it would simply move forward .But if you hit it above or below the center of the ball ,it would rotate as well as translate forward .

In real life friction is present ,but even in an ideal case ,if we assume friction to be absent , a force above or below the center of the ball would cause the ball to rotate.
 
Thanks Tanya! Still are there any other examples which could prove this fact?


koolraj09 said:
Hi all,

Suppose we go in space where no gravity and friction exists. If there is a bar, in say - horizontal plane and we apply a force at one end of the bar, in this plane and perpendicular to the bar. Will that bar rotate and translate or it will only undergo pure translational motion without rotation?
In other words is it sufficient to apply a single force and cause a body to rotate? Or do we need to apply a couple/moment to make the body rotate.

In this example - What 'r' would we take to calculate torque (=rXF)? About which point would the body rotate?
 
  • #10
koolraj09 said:
Still are there any other examples which could prove this fact?
Have you ever kicked a football? Kick it off center and it goes flying and rotates.

In this example - What 'r' would we take to calculate torque (=rXF)? About which point would the body rotate?
It's always convenient to use the center of mass as your reference in calculating 'r'--take r to be the distance from the center of mass. The motion can be consider to be a combination of translation and rotation about the center of mass.
 
  • #11
koolraj09 said:
Thanks Tanya! Still are there any other examples which could prove this fact?

Place a light wooden scale on a sufficiently smooth table .Just flick one end of it with your fingers (i.e give it a sharp impulse ) .You will find the scale rotating as well as moving forward.

koolraj09 said:
In this example - What 'r' would we take to calculate torque (=rXF)? About which point would the body rotate?

'r' is the distance between the point of application of force and the center of mass of the object.

koolraj09 said:
About which point would the body rotate?

The body rotates about its center of mass .

Please note that if a body is unconstrained (i.e free to move ) and an off center force/impulse is applied ,then the body moves such that the center of mass moves in a straight line and the body rotates about the CM .

Hope this helps
 

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