Does the Velocity of the Center of Mass Consider the Spring and m2?

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The discussion centers on the calculation of the center of mass velocity after mass m1 has moved. The formula presented is vcm = m1v1 / (m1 + m2), which is affirmed by participants. There is uncertainty about whether the spring and mass m2 should be factored into the second part of the problem. The conversation reflects a mix of agreement and ambiguity regarding the influence of the spring on the center of mass velocity. Ultimately, the correct approach to the problem remains under debate.
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Homework Statement
Two masses m1 and m2 are at rest and joined by a spring of length l = 0.5m, as shown in the figure. There is no friction with the surface. In a given moment, an impulse with velocity v0 = 0.2m /s is given to the mass m1 only.
Relevant Equations
Calculate the velocity of the center of mass immediately after m1 has moved
Calculate the position of the center of mass after a time t = 4.0s
I want to know if my solution is correct:

The velocity of the center of mass immidiately after m1 has moved is just
vcm=m1v1 /(m1+m2)

I thing that i have to consider the spring and the m2
 
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Zamarripa said:
The velocity of the center of mass immidiately after m1 has moved is just
vcm=m1v1 /(m1+m2)
Yes.
Zamarripa said:
I thing that i have to consider the spring and the m2
For the second part? Maybe... or perhaps not.
 

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