Does the Wave Function Approach Zero at Infinity?

AI Thread Summary
The discussion centers on whether a wave function that approaches zero at infinity implies that its derivative also approaches zero. Participants explore the continuity of wave functions and their derivatives, particularly in the context of normalized solutions to the time-dependent Schrödinger equation with real potential functions. A specific wave function example is proposed to analyze this behavior mathematically. The conversation emphasizes the importance of calculating derivatives directly to confirm assumptions about their limits at infinity. Ultimately, it concludes that while the assumption is commonly accepted, it is not universally guaranteed without verification.
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Homework Statement


If I have a wave function that goes to infinity can I assume that the derivative also goes to 0 at infinity?


Homework Equations





The Attempt at a Solution


The reason I think it does is because the wavefunction and its derivative must be continuous everywhere except at potentials that go to infinity. Is this the correct logic?
 
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Well, this is a little too little information. What is the equation for your wavefunction?
 
We aren't given any. Some other information which might be helpful though, the wave function is normalized, it is a solution to the time dependent schrodinger equation and the potential function is real. And again it approaches zero as x goes to +- infinity. Is that enough?
 
Just that in general the most sure way to decide is to calculate. So, what you should do is write down a wavefunction that satisfies the conditions and see what happens if you differentiate it under your stated conditions.

For example, try to solve this one, you will find it interesting:

\psi(x) = \frac{Asin^{2}x}{\sqrt{x^{2}+1}}
 
I think I see what you are saying. I will give a little more information into what I am trying to do.

The question is:

Consider two normalizable wave functions Ψ1(x, t) and Ψ2(x, t), both of which are solutions
of the time-dependent Schrodinger equation. Assume that the potential function is real.
The functions are normalized, and the functions both approach zero as x goes to ±∞.

Show that these propeties can be used to prove that

\frac{d}{dt} \int_{-∞}^{∞} Ψ1*(x, t)Ψ2(x, t)dx = 0

We get a hint to conert the temporal derivative to the spatial dertivative using the time-dependent schrodinger equation and you get:

\frac{i\bar{h}}{2m} \int_{-∞}^{∞} Ψ1*(x, t)\frac{d^2}{dx^2}Ψ2(x, t) - Ψ2(x, t)\frac{d^2}{dx^2}Ψ1*(x, t)

Then using integration by parts you entually get a term (for one part of the integral) that is

Ψ1*(x, t)\frac{d}{dx}Ψ2(x, t) |^{∞}_{-∞}

and I need that to go to 0 or else the rest doesn't really follow through correctly. I justified it by saying that since Ψ2(x, t) goes to 0 and +- infinity then its derivative will go to 0 and +- infinity.
 
Well, as far as I know, in general it is assumed that

Lim(x \rightarrow ∞) \frac{∂^{n}ψ}{∂x^{n}} = 0

where n is some positive integer

but it does not necessarily have to be the case. As far as I know it is only an assumption.
 
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Okay thank you. I think it is sufficient for my course. I appreciate your time!
 
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