Does the wavelength for photodissociation of hydrogen vary?

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SUMMARY

The photodissociation of hydrogen at ground state requires a photon with a wavelength of 273nm to dissociate H2 into H- and H+. This wavelength is not constant for hydrogen in higher energy states. The relationship between wavelength and energy states can be derived from the frequency-temperature relationship, which is essential for understanding the minimum wavelength required for photodissociation at elevated energy levels. Key terms to research include the Lyman, Balmer, Paschen, Brackett, and Pfund series, which describe the spectral lines of hydrogen.

PREREQUISITES
  • Understanding of photodissociation processes
  • Familiarity with the electromagnetic spectrum
  • Knowledge of the Lyman, Balmer, Paschen, Brackett, and Pfund series
  • Basic principles of quantum mechanics
NEXT STEPS
  • Research the frequency-temperature relationship in quantum mechanics
  • Study the Lyman series and its implications for hydrogen photodissociation
  • Explore the Balmer series and its relevance to higher energy states
  • Investigate the mathematical derivation of minimum wavelength formulas for photodissociation
USEFUL FOR

Students and researchers in physical chemistry, astrophysics, and quantum mechanics, particularly those interested in the photodissociation of hydrogen and its energy state transitions.

Alan Boxx
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Photodissociation of hydrogen at ground state requires a 273nm wavelength for a photon particle to dissociate H2--> H- + H+. But what about hydrogen at higher states of energy? Is the 273nm a constant? If not, what is the formula for min. wavelength for higher energy states (frequency-temperature relationship)? I've researched this quite a bit, but I can't find the answer I'm looking for.
 
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Google "Lyman, Balmer, Paschen, Brackett, Pfund."
 
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Bystander said:
Google "Lyman, Balmer, Paschen, Brackett, Pfund."
Thanks a lot. I'll do my digging.
 

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