Does this equation have any solution?

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The equation x = e^x has no real solutions but does have two complex solutions: x₁ = -W(-1) and x₂ = -W(-1, -1), where W is the Lambert function. The Lambert function can be complex, and both solutions have nonzero imaginary parts. The discussion highlights that for real numbers, the equation lacks solutions, confirmed by graphical analysis and calculus. Understanding the Lambert function is essential for grasping these complex solutions. The conversation emphasizes the distinction between real and complex solutions in this context.
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x\multsp =\multsp {{e}^x}

I'm aware there's no real solution, but does any complex solution exist?
 
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Yes,it has 2 distinct solutions:

x_{1}=-W(-1)

x_{2}=-W(-1,-1)

,where W is the Lambert function.

Daniel.
 
I see. Having read a bit about the Lambert function on Http://www.mathworld.com it doesn't make much sense to me.

Is the following value:

x_{1}=-W(-1)

...a complex number, or something entirely different?
 
You mean a # of nonzero imaginary part...?Yes it is.As u said and as a graph and elementary calculus would show,for real #-s the equation does not have solution.

Daniel.
 
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