I have re-written this as as I accidently deleted my original post. I was wondering if the relativistic Doppler shift of a reflection from a mirror moving away from the observer was the same as the Newtonian equation in the special case that the mirror is orthogonal to the direction of motion.(adsbygoogle = window.adsbygoogle || []).push({});

I referred to equation (13) in this paper http://arxiv.org/ftp/physics/papers/0409/0409014.pdf and set theta to zero for this special case.

I now think I have figured out the answer to my own question.

The equation I gave in my my first post:

[tex] f = f_0 \frac{1-2v/c+v^2/c^2}{1-v^2/c^2} [/tex]

Can be re-arranged:

[tex] f = f_0 \frac{(1-v/c)(1-v/c)}{(1-v/c)(1+v/c)} [/tex]

and simplified:

[tex] f = f_0 \frac{(1-v/c)}{(1+v/c)} [/tex]

and this is exactly the same as the none relativistic equation for Doppler radar.

Length contraction and time dilation is not involved in this special case of reflection in a moving mirror.

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Doppler shift of a signal reflected in a mirror moving away from the observer.

Loading...

Similar Threads for Doppler shift signal |
---|

B Why Light Experienced a Doppler Shift? |

I Redshift and atomic oscillations |

B Visual Effects of Light Travel |

B Why do photons allow Doppler shift |

I Could emission theory produce Doppler-shift formula for moving mirrors? |

**Physics Forums | Science Articles, Homework Help, Discussion**