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Double Integral One Loop of the Rose

  1. Mar 19, 2013 #1
    1. The problem statement, all variables and given/known data

    Use a double integral to find the area of one loop of the rose r = cos 3[itex]\theta[/itex]

    2. Relevant equations



    3. The attempt at a solution

    This is a past test question. The only thing I got wrong was the set up while I got the rest of the mechanical steps right. I set up as

    ∫∫ (r*cos 3θ) dr dθ

    which is not right. I thought it might either be

    ∫∫ (r*r) dr dθ

    or

    ∫∫ (cos 3θ * cos 3θ) dr dθ
     
  2. jcsd
  3. Mar 19, 2013 #2

    SteamKing

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    Hint: r = cos theta, emphasis on equal
     
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