Use double integrals to find the volume of the region in the first octant (x, y, z all more than or equal to zero) bounded by the vertical plane 2x + y = 2 and the surface z = x2
The Attempt at a Solution
I'm having major problems visualizing this, which is stopping me from even getting started.
z = x2 I think I can visualize by itself.
But the plane is confusing me. My prof taught us that to sketch a plane, you find the zeros of the equation. So setting y and z to zero, we find the plane crosses the x axis at 1 and similarly the y axis at 2. But then the plane would be horizontal, not vertical...