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Double integral volume problem

  1. Nov 18, 2014 #1
    1. The problem statement, all variables and given/known data
    find the volume of the solid below the plane z = 4x and above the circle x^2 + y^2 = 16 in the xy plane

    2. Relevant equations


    3. The attempt at a solution
    This totally confused me. I didn't think the plane z = 4x sat above the xy plane. If that is true then there would be no solid between the two graphs. I ended up putting zero for the answer. was I right or wrong
     
  2. jcsd
  3. Nov 18, 2014 #2

    Mark44

    Staff: Mentor

    Part of the z = 4x plane lies above the xy plane. Did you draw a sketch of the plane and the circle?
     
  4. Nov 19, 2014 #3

    Zondrina

    User Avatar
    Homework Helper

    $$\iint_R z \space dA = \iiint_V \space dV$$

    $$\iiint_V \space dV = \iint_R \int_0^z \space dzdA$$

    ;)

    Polar co-ordinates.
     
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