- #1
squenshl
- 479
- 4
For the double integral [tex]\int\int_R[/tex] sqrt(x^2+y^2) dx dy where R is the unit circle.
I got[tex]\int_0^\pi\int_1^1[/tex] sqrt(r2) r dr dtheta
Then after the integration I got an answer of 2[tex]pi[/tex]/3 as my final answer.
Is this right.
The bottom of the 2nd integral is -1 not 1
I got[tex]\int_0^\pi\int_1^1[/tex] sqrt(r2) r dr dtheta
Then after the integration I got an answer of 2[tex]pi[/tex]/3 as my final answer.
Is this right.
The bottom of the 2nd integral is -1 not 1