For the double integral [tex]\int\int_R[/tex] sqrt(x^2+y^2) dx dy where R is the unit circle.(adsbygoogle = window.adsbygoogle || []).push({});

I got[tex]\int_0^\pi\int_1^1[/tex] sqrt(r^{2}) r dr dtheta

Then after the integration I got an answer of 2[tex]pi[/tex]/3 as my final answer.

Is this right.

The bottom of the 2nd integral is -1 not 1

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# Double integral

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