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tiny-tim

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(try using the X

No, for an area you'll only need aI need to find the area between the parabolas x=y^2 and x=2y-y^2, I know I need to use a double integral …

divide the area into strips of width dy, find the area of each strip, and integrate over y.

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HallsofIvy

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The double integral

[itex]\int_{x=a}^b \int_{y= f(x)}^{g(x)} 1 dy dx[/itex]

has a very simple first integral of f(x)- g(x) so that the second integral is

[itex]\int_{x=a}^b f(x)- g(x) dx[/itex]

and that is the integral for area between the curves that tiny-tim is referring to.

So, for your problem, first, determine for what values of x the graphs intersect. That will be your limits of integration a and b for the "outer" integral (a being the smaller, b the larger, of course). The decide which of the graphs is higher inside that interval. That will be f(x) and g(x), the limits of integration for the "inner" integral.

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