- #1
JHans
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Hey, everyone. I'm new to the forums and am hoping that someone can help me with a tricky problem from my multivariable calculus class. We're covering double integrals in polar coordinate systems, and there's a problem from my problem set for homework that I can't seem to get the grasp of.
The question asks: Use a double integral to find the area of the region within both of the circles [tex]r=cos( \theta )[/tex] and [tex]r=sin( \theta )[/tex]
I'm having a lot of difficulty figuring out where to go with this, though. It seems to me that the region is traced by [tex]r=sin( \theta )[/tex] as [tex]\theta[/tex] goes from [tex]0[/tex] to [tex] \pi /4[/tex] and by [tex]r=cos( \theta )[/tex] as [tex]\theta[/tex] goes from [tex]\pi /4[/tex] to [tex]\pi /2[/tex]. Other than that, I'm clueless as to how to solve this using a double integral. Can someone please help me?
The question asks: Use a double integral to find the area of the region within both of the circles [tex]r=cos( \theta )[/tex] and [tex]r=sin( \theta )[/tex]
I'm having a lot of difficulty figuring out where to go with this, though. It seems to me that the region is traced by [tex]r=sin( \theta )[/tex] as [tex]\theta[/tex] goes from [tex]0[/tex] to [tex] \pi /4[/tex] and by [tex]r=cos( \theta )[/tex] as [tex]\theta[/tex] goes from [tex]\pi /4[/tex] to [tex]\pi /2[/tex]. Other than that, I'm clueless as to how to solve this using a double integral. Can someone please help me?