Double slits experiment, wavelength calculation

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SUMMARY

The discussion centers on calculating the wavelength of light in a double slit experiment with slits 1.0 x 10-5 m apart and the first bright band located 3.10 x 10-2 m from the center of a screen 0.65 m away. The relevant formula used is dsin(theta) = (m + 1/2)lambda, where 'd' is the slit separation, 'theta' is the angle, 'm' is the order of the fringe, and 'lambda' is the wavelength. Participants confirm that the angle can be derived from the given distances, allowing for the calculation of the wavelength.

PREREQUISITES
  • Understanding of the double slit experiment
  • Familiarity with the formula dsin(theta) = (m + 1/2)lambda
  • Basic trigonometry to calculate angles
  • Knowledge of fringe patterns in wave optics
NEXT STEPS
  • Calculate the wavelength using the provided distances and the formula dsin(theta) = (m + 1/2)lambda
  • Explore the implications of slit separation on interference patterns
  • Investigate the relationship between wavelength and fringe spacing
  • Learn about advanced applications of the double slit experiment in quantum mechanics
USEFUL FOR

Students studying physics, particularly those focusing on wave optics and interference phenomena, as well as educators seeking to explain the double slit experiment and its implications.

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Homework Statement



In a double slit experiment with slits 1. 10-5 m apart, light casts the first bright band 3.10-2 m from the center of a screen 0.65 m away what is the wavelength ?

Homework Equations



dsin(theta) = (m +1/2)lambda,

The Attempt at a Solution



I think to solve this problem I need the angle more to apply this formula

dsin(theta) = (m +1/2)lambda,

am I right, or maybe we can solve it without the angle ?

Thanks in advance
 
Physics news on Phys.org
If you know the distance to the screen and the distance to the first fringe from the centre line then you have the angle information
 
truesearch said:
If you know the distance to the screen and the distance to the first fringe from the centre line then you have the angle information

Yess sure, thank you.
 

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