Δp/Δt = −ΔEP/Δs why a negative?

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SUMMARY

The formula Δp/Δt = −ΔEP/Δs incorporates a negative sign to indicate the relationship between changes in kinetic energy (ΔKE) and potential energy (ΔPE). This relationship is grounded in the principle of energy conservation, where a loss in potential energy corresponds to an equal gain in kinetic energy, expressed as ΔKE + ΔPE = 0. The force magnitude is derived from the rate of change of kinetic energy with respect to distance, leading to the formulation |F| = -ΔPE/Δs.

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Why is there a minus sign in the formula Δp/Δt = −ΔEP/Δs? Is it because the objects are accelerated toward or away from a higher potential, or is it something else? If anyone could help me, thank you!
 
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S1CkFiSh said:
Why is there a minus sign in the formula Δp/Δt = −ΔEP/Δs? Is it because the objects are accelerated toward or away from a higher potential, or is it something else? If anyone could help me, thank you!
If energy is conserved, there is no overall change in energy. So, when potential energy is lost, the same amount of kinetic energy is gained and vice versa: ΔKE + ΔPE = 0 or ΔKE = - ΔPE.

Since the magnitude of the force can be thought of as the rate of change of kinetic energy with distance (ie since ΔKE = work done = |F|Δs, |F| = ΔKE/Δs -- Δs being the change in distance in the direction of the force) and ΔKE = -ΔPE, then |F| = -ΔPE/Δs.

AM
 

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