Drawing a KMap for f(A,B,C): Step-by-Step Guide

[ckaiser813]

Draw a Kmap for

f(A,B,C) = E m(0,1,3,6,7)

I've had enough expirence with kmap through my digital courses to understand them, but I've never seen them described this way,

AB
00 01 11 10
C 0 1 0 1 0
C 1 1 1 1 0

Is this correct way of drawing it?

 

[berkeman]

Draw a Kmap for

f(A,B,C) = E m(0,1,3,6,7)

I've had enough expirence with kmap through my digital courses to understand them, but I've never seen them described this way,

AB
00 01 11 10
C 0 1 0 1 0
C 1 1 1 1 0

Is this correct way of drawing it?

Looks correct, but if you use the [ code ] [ / code ] tags (without spaces) around the table, it will preserve the spacings.

I haven't seen that notation before either...

 

[berkeman]

     ab
     00 01 11 10
c 0  1  0   1  0
c 1  1  1   1  0

 

[ckaiser813]

thanks for the help I than simplified it to (AB + A'B' + A'C), but when I use a simplifing program it says that I'm correct or it could also be (AB + A'B' + BC). I'm little confused with this one. My professor said once we simplified it we were suppose to find the Static 1 Hazard with this function, do you think the two different answers is what I'm looking for?

 

[berkeman]

thanks for the help I than simplified it to (AB + A'B' + A'C), but when I use a simplifing program it says that I'm correct or it could also be (AB + A'B' + BC). I'm little confused with this one. My professor said once we simplified it we were suppose to find the Static 1 Hazard with this function, do you think the two different answers is what I'm looking for?

Both answer work for that K-map, and I think usually you would pick one based on other considerations (like availability of inverted signals, etc. I'm not seeing the hazard -- am I missing one?

http://en.wikipedia.org/wiki/Hazard_(logic )

.