MHB Drawing vectors according to the phase

aruwin
Messages
204
Reaction score
0
Hi! Ok, I got another question here. I don't understand how to draw the vectors. This is a method to simplify analysis of unbalanced three-phase power systems but I just don't understand the drawing here. Do you think you can explain how? I understand how to draw the vectors for Ia, but not for Ib and Ic. For Ia it's really easy, just draw all of them according to the phase but for Ib and Ic, they seem a little different. I know it's got something to do with the coefficients in the equation but I don't know how to draw according to that, though.
 

Attachments

  • IMG_6671.JPG
    IMG_6671.JPG
    79.7 KB · Views: 101
Physics news on Phys.org
I am having trouble reading the subscripts - about the only one I can discern for certain is Ia but the drawing is adding (or subtracting) vectors. The vectors to be summed are placed with one starting at the origin and all the others head to tail (the origin of the second vector is at the head of the 1st vector); then a vector drawn from the origin to the head of the last component vector is the sum.
 
Last edited:
We all know the definition of n-dimensional topological manifold uses open sets and homeomorphisms onto the image as open set in ##\mathbb R^n##. It should be possible to reformulate the definition of n-dimensional topological manifold using closed sets on the manifold's topology and on ##\mathbb R^n## ? I'm positive for this. Perhaps the definition of smooth manifold would be problematic, though.

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 12 ·
Replies
12
Views
4K
  • · Replies 17 ·
Replies
17
Views
1K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 49 ·
2
Replies
49
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
7
Views
948
  • · Replies 3 ·
Replies
3
Views
2K