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Driven Damped Harmonic Oscillator, f != ma??
Let's say I've got a driven damped harmonic oscillator described by the following equation:
A \ddot{x} + B \dot{x} + C x = D f(t)
given that f = ma why can't I write
A \ddot{x} + B \dot{x} + C x = D ma
substitute \ddot{x} = a to get
A \ddot{x} + B \dot{x} + C x = D m \ddot{x}
and then rearrange to get
(A - D m) \ddot{x} + B \dot{x} + C x = 0
I know that's not how the problem is solved, but what is to stop me from solving it that way?
Let's say I've got a driven damped harmonic oscillator described by the following equation:
A \ddot{x} + B \dot{x} + C x = D f(t)
given that f = ma why can't I write
A \ddot{x} + B \dot{x} + C x = D ma
substitute \ddot{x} = a to get
A \ddot{x} + B \dot{x} + C x = D m \ddot{x}
and then rearrange to get
(A - D m) \ddot{x} + B \dot{x} + C x = 0
I know that's not how the problem is solved, but what is to stop me from solving it that way?
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