Dropping coal on a platfrom (energy cons)

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The discussion revolves around a physics problem involving a railroad hopper car releasing coal onto a platform. The car, weighing 20,000 kg and carrying 10,000 kg of coal, maintains a speed of 9 m/s as it dumps the coal over 5 seconds. Key calculations include the momentum absorbed by the platform, which is 9,000 kg/m/s, and the average horizontal force on the platform, calculated at 9,000 N. A critical point raised is the conservation of energy, questioning how energy is conserved when the coal comes to rest, leading to the conclusion that both kinetic and potential energy are converted to heat. The total energy converted during this process is determined to be 895,000 J.
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Homework Statement


A railroad hopper car weighs 20000 kg when empty and contains 10000 kg of coal. As it coasts along the track at 9 m/s the hopper opens and steadily releases all the coal onto a platform below the rails over a period of 5 s.


Homework Equations


d) If the coal fell 5 m, what was the total energy converted to heat in the process of the coal coming to rest?


The Attempt at a Solution



Ive already got the first 3 parts of this question. they are
How fast does the car travel after all the coal is dumped?
=9m/s

What was the momentum absorbed by the platform?
=9000kg/m/s

If the coal comes to rest 1 second after the dumping is finished, what was the average horizontal force on the platform?
=9000N

My question b4 attemptin solution is --how can energy be conserved if coal is at rest? (no potential, and no kinetic).
If it cant, then that would mean all the energy must have gone somewhere.. --heat.

So 9000N*5m = 45000J.
This is wrong.
??
 
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You are correct about energy being conserved, what two types of energy does the coal have when it is moving in the train?
When it comes to rest below the train it loses both of these - to heat as you said.
 
AHA potential AND kinetic because car moving 9ms
so Ek + Ep = 895000J

thanks!
 
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