[PLAIN]http://www.bpp.com.pl/IMG/faint.gif[/QUOTE]
Sorry Borek, didnt mean to make you faint and hit your head. I don't have any idea how I came up with that number, I have tried repeatedly to come up with it again and I have not been even close to being successful.
Here goes my next try, a ten wheeler gets about 4-7mpg, taking the lower end, one quarter of a gallon will cover one mile, the energy density of diesel is 45.3 MJ/kg, one gallon of diesel weighs 3.402 kg so one quart would weigh .8505 kg, which would leave us at 38.53 MJ/mile(one pass around 9 foot wide). Is this close or have you just fainted again?
Assuming this try at math was successful, it would take 4 passes to completely clean a one mile section of 2 lane highway from shoulder to shoulder with the plow, which would make it 154.12 MJ of energy expended. According to Mech Engineer (post #51), to get the same area to melt one inch of snow it would take 2.3MW/h. 2.3 MW/h converts to 8280 MJ, so it would take 53.72 times more energy to melt the snow. If it takes pretty much the same energy to plow 1 foot as it does to plow 1 inch, the difference in energy expenditures between plowing and heating would be even more enormous(since it already is for an inch), and that's before we even discuss the added costs of building the heated roads, maintaining them and storage facilities for the energy they make.
As you probably already know, I'm no mathmatician nor a physicist or even a college graduate, so please correct me where it is needed. I am here to learn but fainting emoticons don't teach me much other than that I was wrong. If this thread is not the place to further this discussion, could you please PM me an explanation of where I went wrong. Thanks.