Dynamics of uniform circular motion and bohr model

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In the discussion on the dynamics of uniform circular motion and the Bohr model, participants analyze the motion of an electron orbiting a proton in a hydrogen atom. The electric force acting on the electron is given as 9.2 x 10^-8 N, and the distance from the proton is 5.3 x 10^-11 m. Using the formula F = mV^2/R, the velocity of the electron is calculated to be approximately 1.64 x 10^6 m/s. The time for one revolution, or period, is derived from the relationship between distance and velocity, leading to the conclusion that the distance provided is indeed the radius, not the diameter. Ultimately, the discussion clarifies the calculations needed to determine the revolutions per second of the electron.
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In the Bohr model of the hydrogen atom, an electron (mass m = 9.1 x 10^-31 kg) orbits a proton at a distance of 5.3 x 10^-11 m. The proton pulls on the electron with an electric force of 9.2 x 10^-8 N. How many revolutions per second does the electron make?

can someone help me solve this problem?
 
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first of all
:mad: :mad: :mad:

SHOW SOME WORK we're not here to do your work for you!

Secondly F = m V^2 / R

Secondly distance / velocity = time

what is the distance traveled by this electron ? Is it a straight line or something else? If it something else , isn't htat something else defined by some formula?

The time given in the above formula represents something, what does it represent?

All the clues are here, show some work and i'd have been more helpful
 
sorry i had done the problem but it was incorrect so i figured i would start from scratch. anyways i did complete some parts that are still useful. using F = mv^2/r
i got the velocity = sqrt(F*r/m) so v = 1636802. for radius am i correct in assuming that the distance given is the diameter? if so, i got a time of 3.23 x 10^-17 s. the electron is orbiting a proton so do i use the time as the period and compute the velocity using v = 2*pi*r/T(period) ?
 
ok i figured it out. thanks for your hints. basically i didn't realize that the distance given was the actual distance instead of my dividing it by two to get a radius. so i just used v = sqrt((distance * force)/ mass) to get the velocity and then to get the angular velocity i just did velocity / distance. then converted from radians to rev/s.
 
quick said:
sorry i had done the problem but it was incorrect so i figured i would start from scratch. anyways i did complete some parts that are still useful. using F = mv^2/r
i got the velocity = sqrt(F*r/m) so v = 1636802. for radius am i correct in assuming that the distance given is the diameter? if so, i got a time of 3.23 x 10^-17 s. the electron is orbiting a proton so do i use the time as the period and compute the velocity using v = 2*pi*r/T(period) ?

exactly

period is given by 2 pi r / v or if you care for angular velocity w = v/ r then T = 2 pi / w and you're done like dinner
 

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