Dynamics question. inclined plane

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An object weighing 10 kg is raised 2 meters using an inclined plane with a friction coefficient of 0.5. The discussion centers on calculating the work needed to overcome both gravitational and frictional forces, particularly after the object reaches a maximum velocity of 1 m/s after 1 meter. The initial calculation of work done using the work-energy principle yields 5 J, but this does not account for friction, which must be included in the total force calculation. Participants suggest considering the frictional force throughout the movement and re-evaluating the problem with the complete context of the original question. Accurate calculations are essential for determining the correct amount of work required.
Raye
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Hi guys

can you help me with this question? any hint is helpful..



an object of weight of 10 kg is to be raised 2 m off ground. there's an inclined plane for it with a freely chosen angle. How much work must be applied for the plane with 0.5 friction when after 1 m , the object its max. velocity of 1 m/s reaches? (it starts moving from 0 m/s)

My theory: after 1m there'll be no acceleration, thus the work would be zero. everything regarding to 0 to 1 m work could be calculated by the work and energy law: W=K_2 - K_1

the energy in the end minus the initial energy: W: 1/2 m v^2-0 = 5 J
The F was originally the one without friction thus:

F: 5+(FN*0.5)

which is not correct since the result is 371.19
 
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Hi Raye,

Maybe we'll have more luck if you could please post the exact text of the original question. But at a minimum, you're definitely going to need to consider the friction on the ramp; keep in mind that work = force times distance, and the whole time you are pushing against those friction forces as you slide up the ramp, as well as lifting the box. Give that some thought, and if you're still stuck please post the original text of the question and we'll try again; apologies in advance if I've misinterpreted your question,

Hope this helps,
Bill Mills
 
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