Hey! I'm having some problems with this question: An electric winch is used to raise a 40-kg package and a 10-kg package vertically up the side of a building as pictured in the diagram. The magnitude of the frictional force acting between the wall and the 40-kg package is 60N. The angle the cable makes to the vertical is 15. If the packages are lowered with an acceleration 1.0 m/s2 [D], what is the tension in the cable between the winch and the 40.0 kg package? We were also given a diagram: http://i1289.photobucket.com/albums/b505/homework2012/Untitled_zpsd252a02a.jpg How i solved it: (1) Fnet y= Fg1+Fg2+T2+T1Y+FK mnet(anet)= Fg1+Fg2-T2-T1Y-FK (2) Fnet=Fg+T2 ma=m2g-T2 (10)(0.1)=(10)(9.8)-T2 T2 = 88N (3) mnet(anet)= Fg1+Fg2-T2-T1Y-FK (50)(0.1)= 40(9.8) + 10(9.8) -88 -T1Y- 60 T1Y= 292N (4) Sin?=o/h Sin75=292/h h = 302.3 N Is how i solved it right? If not is there another way I should be solving it?