Solving a Vertical Winch System

In summary, the problem involves an electric winch lifting a 40-kg package and a 10-kg package up a building. The frictional force between the wall and the 40-kg package is 60N and the angle the cable makes with the vertical is 15 degrees. The packages are being lowered with an acceleration of 1.0 m/s2 [D]. To find the tension in the cable between the winch and the 40.0 kg package, a force diagram for each block must be drawn and the correct numbers must be used in the equations. The solution involves finding the tension in the cable between the winch and the 10-kg package and then using that to find the tension between the
  • #1
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Hey! I'm having some problems with this question:
An electric winch is used to raise a 40-kg package and a 10-kg package vertically up the side of a building as pictured in the diagram. The magnitude of the frictional force acting between the wall and the 40-kg package is 60N. The angle the cable makes to the vertical is 15. If the packages are lowered with an acceleration 1.0 m/s2 [D], what is the tension in the cable between the winch and the 40.0 kg package?

We were also given a diagram:
http://i1289.photobucket.com/albums/b505/homework2012/Untitled_zpsd252a02a.jpg

How i solved it:
(1) Fnet y= Fg1+Fg2+T2+T1Y+FK
mnet(anet)= Fg1+Fg2-T2-T1Y-FK
(2) Fnet=Fg+T2
ma=m2g-T2
(10)(0.1)=(10)(9.8)-T2
T2 = 88N
(3) mnet(anet)= Fg1+Fg2-T2-T1Y-FK
(50)(0.1)= 40(9.8) + 10(9.8) -88 -T1Y- 60
T1Y= 292N
(4) Sin?=o/h
Sin75=292/h
h = 302.3 N

Is how i solved it right? If not is there another way I should be solving it?
 
Last edited:
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  • #2
Draw a force diagram for each block separately. (1) and (3) are wrong. You also didn't use the right numbers when you plugged into (2).
 

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